30x^2+28x+6=0

Solution for 30x^2+28x+6=0 equation:

30x^2+28x+6=0

a = 30; b = 28; c = +6;
Δ = b2-4ac
Δ = 282-4·30·6
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-8}{2*30}=\frac{-36}{60}
=-3/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+8}{2*30}=\frac{-20}{60}
=-1/3
$